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➜ MUSHclient
➜ VBscript
➜ Stuck in it badly
It is now over 60 days since the last post. This thread is closed.
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| Posted by
| Nickpick
(24 posts) Bio
|
| Date
| Sat 08 Apr 2006 06:37 PM (UTC) |
| Message
| I've got a problem! Again!
I've got this piece of script, which works in the IMMEDIATE mode, but refuses to work while put into a trigger:
///
set re = new regexp
stringe = "You remove 1 goldenseal root, bringing the total in the Rift to 38."
With re
.Pattern = "^(You remove) (\d|\d\d|\d\d\d|\d\d\d\d) (goldenseal root, bringing the total in the Rift to) (\d|\d\d|\d\d\d|\d\d\d\d)(.)$"
.IgnoreCase = False
.Global = False
End With
ma = re.test(stringe)
world.note ma
world.enabletrigger "GoldensealOUTR", "true"
///
Basically it's supposed to give out -1 and it does, in immediate mode. However, once I insert it into a trigger and make it fire, it gives out 0. Help? | | Top |
|
| Posted by
| Nickpick
(24 posts) Bio
|
| Date
| Reply #1 on Sat 08 Apr 2006 07:18 PM (UTC) |
| Message
| Issue solved. Incredibly bizarre nevertheless.
///
set re = new regexp
stringe = "%1"
With re
.Pattern = "^(You remove) ([0-9]|[0-9][0-9]|[0-9][0-9][0-9]|[0-9][0-9][0-9][0-9]) (goldenseal root, bringing the total in the Rift to) ([0-9]|[0-9][0-9]|[0-9][0-9][0-9]|[0-9][0-9][0-9][0-9])(.)$"
.IgnoreCase = False
.Global = False
End With
ma = re.test(stringe)
world.note ma
world.enabletrigger "GoldensealOUTR", "true"
///
Just had to replace \d with [0-9]. Funnily enough \d still worked in the IMMEDIATE. Oh well.. | | Top |
|
| Posted by
| Nick Gammon
Australia (23,133 posts) Bio
Forum Administrator |
| Date
| Reply #2 on Sun 09 Apr 2006 04:14 AM (UTC) |
| Message
| | I think in the trigger window, MUSHclient processes sequences like \n to be newlines, so your solution would have been to make \d into \\d in that case. |
- Nick Gammon
www.gammon.com.au, www.mushclient.com | | Top |
|
| Posted by
| Nick Gammon
Australia (23,133 posts) Bio
Forum Administrator |
| Date
| Reply #3 on Tue 13 Jun 2006 09:31 PM (UTC) |
| Message
|
(\d|\d\d|\d\d\d|\d\d\d\d)
...
([0-9]|[0-9][0-9]|[0-9][0-9][0-9]|[0-9][0-9][0-9][0-9])
Both of these can be simplified by using the "count" syntax:
(\d{1,4})
...
([0-9]{1,4})
|
- Nick Gammon
www.gammon.com.au, www.mushclient.com | | Top |
|
| Posted by
| NeoFryBoy
USA (42 posts) Bio
|
| Date
| Reply #4 on Tue 04 Jul 2006 08:50 AM (UTC) |
| Message
| Would...
^(You remove) (\d+) (goldenseal root, bringing the total in the Rift to) (\d+)\.$
...be just as fast? | | Top |
|
| Posted by
| Nick Gammon
Australia (23,133 posts) Bio
Forum Administrator |
| Date
| Reply #5 on Tue 04 Jul 2006 09:42 PM (UTC) |
| Message
| | They would both be fast enough, the original one matches on 1-4 digits, yours would match on 1 to any number. Unless there was some obscure problem with mismatches (eg. with a 5 digit number) your solution is probably more elegant. |
- Nick Gammon
www.gammon.com.au, www.mushclient.com | | Top |
|
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